How to create own dynamic type or dynamic object in C#?
How to create own dynamic type or dynamic object in C#? – Stack Overflow
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There, is for example, ViewBag property of ControllerBase class and we can dynamically get/set values and add any number of additional fields or properties to this object, which is cool .I want to use something like that, beyond MVC application and Controller class in other types of applications. When I tried to create dynamic object and set it’s property like below:
I’ve got RuntimeBinderException with message Property or indexer ‘f__AnonymousType0.A’ cannot be assigned to — it is read only in line 2. Also I suggest It’s not quite what I’m looking-for. Maybe is there some class which can allow me to do something like:
with dynamic adding and setting properties.
asked Oct 3 ’12 at 13:17
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dynamic MyDynamic = new System.Dynamic.ExpandoObject(); MyDynamic.A = “A”; MyDynamic.B = “B”; MyDynamic.C = “C”; MyDynamic.Number = 12; MyDynamic.MyMethod = new Func(() => { return 55; }); Console.WriteLine(MyDynamic.MyMethod());Read more about ExpandoObject class and for more samples: Represents an object whose members can be dynamically added and removed at run time.
answered Oct 3 ’12 at 13:21
Mario SMario S11.2k2424 gold badges3636 silver badges4646 bronze badges
1I recently had a need to take this one step further, which was to make the property additions in the dynamic object, dynamic themselves, based on user defined entries. The examples here, and from Microsoft’s ExpandoObject documentation, do not specifically address adding properties dynamically, but, can be surmised from how you enumerate and delete properties. Anyhow, I thought this might be helpful to someone. Here is an extremely simplified version of how to add truly dynamic properties to an ExpandoObject (ignoring keyword and other handling):
// my pretend dataset List fields = new List(); // my ‘columns’ fields.Add(“this_thing”); fields.Add(“that_thing”); fields.Add(“the_other”); dynamic exo = new System.Dynamic.ExpandoObject(); foreach (string field in fields) { ((IDictionary)exo).Add(field, field + “_data”); } // output – from Json.Net NuGet package textBox1.Text = Newtonsoft.Json.JsonConvert.SerializeObject(exo);answered Aug 29 ’16 at 14:58
AlienFromCAAlienFromCA7231111 silver badges1717 bronze badges
3ExpandoObject is what are you looking for.
dynamic MyDynamic = new ExpandoObject(); // note, the type MUST be dynamic to use dynamic invoking. MyDynamic.A = “A”; MyDynamic.B = “B”; MyDynamic.C = “C”; MyDynamic.TheAnswerToLifeTheUniverseAndEverything = 42;answered Oct 3 ’12 at 13:21
nothrownothrow15.1k66 gold badges5151 silver badges100100 bronze badges
dynamic myDynamic = new { PropertyOne = true, PropertyTwo = false}; Andrew15.1k99 gold badges8787 silver badges9898 bronze badges
answered Oct 17 ’19 at 15:19
smedasnsmedasn9031010 silver badges1313 bronze badges
var data = new { studentId = 1, StudentName = “abc” };Or value is present
var data = new { studentId, StudentName };answered Nov 19 ’19 at 12:42
RockRock40555 silver badges1414 bronze badges
1You can use ExpandoObject Class which is in System.Dynamic namespace.
dynamic MyDynamic = new ExpandoObject(); MyDynamic.A = “A”; MyDynamic.B = “B”; MyDynamic.C = “C”; MyDynamic.SomeProperty = SomeValue MyDynamic.number = 10; MyDynamic.Increment = (Action)(() => { MyDynamic.number++; });More Info can be found at ExpandoObject MSDN
answered Oct 3 ’12 at 13:55
Kishore KumarKishore Kumar12.1k2626 gold badges9090 silver badges151151 bronze badges
dynamic MyDynamic = new ExpandoObject();answered Oct 3 ’12 at 13:23
DaveczDavecz1,17811 gold badge1818 silver badges4040 bronze badges
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How to create own dynamic type or dynamic object in C#?
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